1Z0-851 Actual exam Preparation

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Oracle 1Z0-851 Exam Sample Questions

Question: 1

Given a pre-generics implementation of a method:

11. public static int sum(List list) {

12. int sum = 0;

13. for ( Iterator iter = list.iterator(); iter.hasNext(); ) {

14. int i = ((Integer)iter.next()).intValue();

15. sum += i;

16. }

17. return sum;

18. }

What three changes allow the class to be used with generics and avoid an unchecked warning?

(Choose three.)

  1. Remove line 14.
  2. Replace line 14 with “int i = iter.next();”.
  3. Replace line 13 with “for (int i : intList) {“.
  4. Replace line 13 with “for (Iterator iter : intList) {“.
  5. Replace the method declaration with “sum(List intList)”.
  • Replace the method declaration with “sum(List intList)”.

  • Answer: A,C,F

    Question: 4

    Given:

    12. import java.util.*;

    13. public class Explorer2 {

    14. public static void main(String[] args) {

    15. TreeSet s = new TreeSet();

    16. TreeSet subs = new TreeSet();

    17. for(int i = 606; i < 613; i++)

    18. if(i%2 == 0) s.add(i);

    19. subs = (TreeSet)s.subSet(608, true, 611, true);

    20. s.add(629);

    21. System.out.println(s + ” ” + subs);

    22. }

    23. }

    What is the result?

    1. Compilation fails.
    2. An exception is thrown at runtime.
    3. [608, 610, 612, 629] [608, 610]
    4. [608, 610, 612, 629] [608, 610, 629]
    5. [606, 608, 610, 612, 629] [608, 610]
  • [606, 608, 610, 612, 629] [608, 610, 629]

  • Answer: E

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    Each time your youngster receives a tutor, they may not strike it off properly together with the tutor and you simply also could have to have to talk to them more than it and likewise track Oracle Java Standard Edition 6 Programmer Certified Professional Exam down 1 extra tutor. Oracle Java real 1Z0-851 questions The essential aspect is you would like to identify a tutor who works appropriately with all your toddler and along with you.

    Question: 4

    Given:

    12. import java.util.*;

    13. public class Explorer2 {

    14. public static void main(String[] args) {

    15. TreeSet s = new TreeSet();

    16. TreeSet subs = new TreeSet();

    17. for(int i = 606; i < 613; i++)

    18. if(i%2 == 0) s.add(i);

    19. subs = (TreeSet)s.subSet(608, true, 611, true);

    20. s.add(629);

    21. System.out.println(s + ” ” + subs);

    22. }

    23. }

    What is the result?

    1. Compilation fails.
    2. An exception is thrown at runtime.
    3. [608, 610, 612, 629] [608, 610]
    4. [608, 610, 612, 629] [608, 610, 629]
    5. [606, 608, 610, 612, 629] [608, 610]
  • [606, 608, 610, 612, 629] [608, 610, 629]

  • Answer: E

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    Question: 2

    A programmer has an algorithm that requires a java.util.List that provides an efficient implementation of add(0, object), but does NOT need to support quick random access. What supports these requirements?

    1. java.util.Queue
    2. java.util.ArrayList
    3. java.util.LinearList
    4. java.util.LinkedList


    Answer: D

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    Question: 1

    Given a pre-generics implementation of a method:

    11. public static int sum(List list) {

    12. int sum = 0;

    13. for ( Iterator iter = list.iterator(); iter.hasNext(); ) {

    14. int i = ((Integer)iter.next()).intValue();

    15. sum += i;

    16. }

    17. return sum;

    18. }

    What three changes allow the class to be used with generics and avoid an unchecked warning?

    (Choose three.)

    1. Remove line 14.
    2. Replace line 14 with “int i = iter.next();”.
    3. Replace line 13 with “for (int i : intList) {“.
    4. Replace line 13 with “for (Iterator iter : intList) {“.
    5. Replace the method declaration with “sum(List intList)”.
  • Replace the method declaration with “sum(List intList)”.

  • Answer: A,C,F

    Question: 4

    Given:

    12. import java.util.*;

    13. public class Explorer2 {

    14. public static void main(String[] args) {

    15. TreeSet s = new TreeSet();

    16. TreeSet subs = new TreeSet();

    17. for(int i = 606; i < 613; i++)

    18. if(i%2 == 0) s.add(i);

    19. subs = (TreeSet)s.subSet(608, true, 611, true);

    20. s.add(629);

    21. System.out.println(s + ” ” + subs);

    22. }

    23. }

    What is the result?

    1. Compilation fails.
    2. An exception is thrown at runtime.
    3. [608, 610, 612, 629] [608, 610]
    4. [608, 610, 612, 629] [608, 610, 629]
    5. [606, 608, 610, 612, 629] [608, 610]
  • [606, 608, 610, 612, 629] [608, 610, 629]

  • Answer: E

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